3.1.100 \(\int \frac {x^3 (a+b \log (c x^n))^2}{(d+e x)^2} \, dx\) [100]

Optimal. Leaf size=281 \[ \frac {4 a b d n x}{e^3}-\frac {4 b^2 d n^2 x}{e^3}+\frac {b^2 n^2 x^2}{4 e^2}+\frac {4 b^2 d n x \log \left (c x^n\right )}{e^3}-\frac {b n x^2 \left (a+b \log \left (c x^n\right )\right )}{2 e^2}-\frac {2 d x \left (a+b \log \left (c x^n\right )\right )^2}{e^3}+\frac {x^2 \left (a+b \log \left (c x^n\right )\right )^2}{2 e^2}-\frac {d^2 x \left (a+b \log \left (c x^n\right )\right )^2}{e^3 (d+e x)}+\frac {2 b d^2 n \left (a+b \log \left (c x^n\right )\right ) \log \left (1+\frac {e x}{d}\right )}{e^4}+\frac {3 d^2 \left (a+b \log \left (c x^n\right )\right )^2 \log \left (1+\frac {e x}{d}\right )}{e^4}+\frac {2 b^2 d^2 n^2 \text {Li}_2\left (-\frac {e x}{d}\right )}{e^4}+\frac {6 b d^2 n \left (a+b \log \left (c x^n\right )\right ) \text {Li}_2\left (-\frac {e x}{d}\right )}{e^4}-\frac {6 b^2 d^2 n^2 \text {Li}_3\left (-\frac {e x}{d}\right )}{e^4} \]

[Out]

4*a*b*d*n*x/e^3-4*b^2*d*n^2*x/e^3+1/4*b^2*n^2*x^2/e^2+4*b^2*d*n*x*ln(c*x^n)/e^3-1/2*b*n*x^2*(a+b*ln(c*x^n))/e^
2-2*d*x*(a+b*ln(c*x^n))^2/e^3+1/2*x^2*(a+b*ln(c*x^n))^2/e^2-d^2*x*(a+b*ln(c*x^n))^2/e^3/(e*x+d)+2*b*d^2*n*(a+b
*ln(c*x^n))*ln(1+e*x/d)/e^4+3*d^2*(a+b*ln(c*x^n))^2*ln(1+e*x/d)/e^4+2*b^2*d^2*n^2*polylog(2,-e*x/d)/e^4+6*b*d^
2*n*(a+b*ln(c*x^n))*polylog(2,-e*x/d)/e^4-6*b^2*d^2*n^2*polylog(3,-e*x/d)/e^4

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Rubi [A]
time = 0.22, antiderivative size = 281, normalized size of antiderivative = 1.00, number of steps used = 13, number of rules used = 10, integrand size = 23, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.435, Rules used = {2395, 2333, 2332, 2342, 2341, 2355, 2354, 2438, 2421, 6724} \begin {gather*} \frac {6 b d^2 n \text {PolyLog}\left (2,-\frac {e x}{d}\right ) \left (a+b \log \left (c x^n\right )\right )}{e^4}+\frac {2 b^2 d^2 n^2 \text {PolyLog}\left (2,-\frac {e x}{d}\right )}{e^4}-\frac {6 b^2 d^2 n^2 \text {PolyLog}\left (3,-\frac {e x}{d}\right )}{e^4}+\frac {2 b d^2 n \log \left (\frac {e x}{d}+1\right ) \left (a+b \log \left (c x^n\right )\right )}{e^4}+\frac {3 d^2 \log \left (\frac {e x}{d}+1\right ) \left (a+b \log \left (c x^n\right )\right )^2}{e^4}-\frac {d^2 x \left (a+b \log \left (c x^n\right )\right )^2}{e^3 (d+e x)}-\frac {2 d x \left (a+b \log \left (c x^n\right )\right )^2}{e^3}-\frac {b n x^2 \left (a+b \log \left (c x^n\right )\right )}{2 e^2}+\frac {x^2 \left (a+b \log \left (c x^n\right )\right )^2}{2 e^2}+\frac {4 a b d n x}{e^3}+\frac {4 b^2 d n x \log \left (c x^n\right )}{e^3}-\frac {4 b^2 d n^2 x}{e^3}+\frac {b^2 n^2 x^2}{4 e^2} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(x^3*(a + b*Log[c*x^n])^2)/(d + e*x)^2,x]

[Out]

(4*a*b*d*n*x)/e^3 - (4*b^2*d*n^2*x)/e^3 + (b^2*n^2*x^2)/(4*e^2) + (4*b^2*d*n*x*Log[c*x^n])/e^3 - (b*n*x^2*(a +
b*Log[c*x^n]))/(2*e^2) - (2*d*x*(a + b*Log[c*x^n])^2)/e^3 + (x^2*(a + b*Log[c*x^n])^2)/(2*e^2) - (d^2*x*(a +
b*Log[c*x^n])^2)/(e^3*(d + e*x)) + (2*b*d^2*n*(a + b*Log[c*x^n])*Log[1 + (e*x)/d])/e^4 + (3*d^2*(a + b*Log[c*x
^n])^2*Log[1 + (e*x)/d])/e^4 + (2*b^2*d^2*n^2*PolyLog[2, -((e*x)/d)])/e^4 + (6*b*d^2*n*(a + b*Log[c*x^n])*Poly
Log[2, -((e*x)/d)])/e^4 - (6*b^2*d^2*n^2*PolyLog[3, -((e*x)/d)])/e^4

Rule 2332

Int[Log[(c_.)*(x_)^(n_.)], x_Symbol] :> Simp[x*Log[c*x^n], x] - Simp[n*x, x] /; FreeQ[{c, n}, x]

Rule 2333

Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))^(p_.), x_Symbol] :> Simp[x*(a + b*Log[c*x^n])^p, x] - Dist[b*n*p, In
t[(a + b*Log[c*x^n])^(p - 1), x], x] /; FreeQ[{a, b, c, n}, x] && GtQ[p, 0] && IntegerQ[2*p]

Rule 2341

Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))*((d_.)*(x_))^(m_.), x_Symbol] :> Simp[(d*x)^(m + 1)*((a + b*Log[c*x^
n])/(d*(m + 1))), x] - Simp[b*n*((d*x)^(m + 1)/(d*(m + 1)^2)), x] /; FreeQ[{a, b, c, d, m, n}, x] && NeQ[m, -1
]

Rule 2342

Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))^(p_.)*((d_.)*(x_))^(m_.), x_Symbol] :> Simp[(d*x)^(m + 1)*((a + b*Lo
g[c*x^n])^p/(d*(m + 1))), x] - Dist[b*n*(p/(m + 1)), Int[(d*x)^m*(a + b*Log[c*x^n])^(p - 1), x], x] /; FreeQ[{
a, b, c, d, m, n}, x] && NeQ[m, -1] && GtQ[p, 0]

Rule 2354

Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))^(p_.)/((d_) + (e_.)*(x_)), x_Symbol] :> Simp[Log[1 + e*(x/d)]*((a +
b*Log[c*x^n])^p/e), x] - Dist[b*n*(p/e), Int[Log[1 + e*(x/d)]*((a + b*Log[c*x^n])^(p - 1)/x), x], x] /; FreeQ[
{a, b, c, d, e, n}, x] && IGtQ[p, 0]

Rule 2355

Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))^(p_.)/((d_) + (e_.)*(x_))^2, x_Symbol] :> Simp[x*((a + b*Log[c*x^n])
^p/(d*(d + e*x))), x] - Dist[b*n*(p/d), Int[(a + b*Log[c*x^n])^(p - 1)/(d + e*x), x], x] /; FreeQ[{a, b, c, d,
e, n, p}, x] && GtQ[p, 0]

Rule 2395

Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))^(p_.)*((f_.)*(x_))^(m_.)*((d_) + (e_.)*(x_)^(r_.))^(q_.), x_Symbol]
:> With[{u = ExpandIntegrand[(a + b*Log[c*x^n])^p, (f*x)^m*(d + e*x^r)^q, x]}, Int[u, x] /; SumQ[u]] /; FreeQ[
{a, b, c, d, e, f, m, n, p, q, r}, x] && IntegerQ[q] && (GtQ[q, 0] || (IGtQ[p, 0] && IntegerQ[m] && IntegerQ[r
]))

Rule 2421

Int[(Log[(d_.)*((e_) + (f_.)*(x_)^(m_.))]*((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))^(p_.))/(x_), x_Symbol] :> Simp
[(-PolyLog[2, (-d)*f*x^m])*((a + b*Log[c*x^n])^p/m), x] + Dist[b*n*(p/m), Int[PolyLog[2, (-d)*f*x^m]*((a + b*L
og[c*x^n])^(p - 1)/x), x], x] /; FreeQ[{a, b, c, d, e, f, m, n}, x] && IGtQ[p, 0] && EqQ[d*e, 1]

Rule 2438

Int[Log[(c_.)*((d_) + (e_.)*(x_)^(n_.))]/(x_), x_Symbol] :> Simp[-PolyLog[2, (-c)*e*x^n]/n, x] /; FreeQ[{c, d,
e, n}, x] && EqQ[c*d, 1]

Rule 6724

Int[PolyLog[n_, (c_.)*((a_.) + (b_.)*(x_))^(p_.)]/((d_.) + (e_.)*(x_)), x_Symbol] :> Simp[PolyLog[n + 1, c*(a
+ b*x)^p]/(e*p), x] /; FreeQ[{a, b, c, d, e, n, p}, x] && EqQ[b*d, a*e]

Rubi steps

\begin {align*} \int \frac {x^3 \left (a+b \log \left (c x^n\right )\right )^2}{(d+e x)^2} \, dx &=\int \left (-\frac {2 d \left (a+b \log \left (c x^n\right )\right )^2}{e^3}+\frac {x \left (a+b \log \left (c x^n\right )\right )^2}{e^2}-\frac {d^3 \left (a+b \log \left (c x^n\right )\right )^2}{e^3 (d+e x)^2}+\frac {3 d^2 \left (a+b \log \left (c x^n\right )\right )^2}{e^3 (d+e x)}\right ) \, dx\\ &=-\frac {(2 d) \int \left (a+b \log \left (c x^n\right )\right )^2 \, dx}{e^3}+\frac {\left (3 d^2\right ) \int \frac {\left (a+b \log \left (c x^n\right )\right )^2}{d+e x} \, dx}{e^3}-\frac {d^3 \int \frac {\left (a+b \log \left (c x^n\right )\right )^2}{(d+e x)^2} \, dx}{e^3}+\frac {\int x \left (a+b \log \left (c x^n\right )\right )^2 \, dx}{e^2}\\ &=-\frac {2 d x \left (a+b \log \left (c x^n\right )\right )^2}{e^3}+\frac {x^2 \left (a+b \log \left (c x^n\right )\right )^2}{2 e^2}-\frac {d^2 x \left (a+b \log \left (c x^n\right )\right )^2}{e^3 (d+e x)}+\frac {3 d^2 \left (a+b \log \left (c x^n\right )\right )^2 \log \left (1+\frac {e x}{d}\right )}{e^4}-\frac {\left (6 b d^2 n\right ) \int \frac {\left (a+b \log \left (c x^n\right )\right ) \log \left (1+\frac {e x}{d}\right )}{x} \, dx}{e^4}+\frac {(4 b d n) \int \left (a+b \log \left (c x^n\right )\right ) \, dx}{e^3}+\frac {\left (2 b d^2 n\right ) \int \frac {a+b \log \left (c x^n\right )}{d+e x} \, dx}{e^3}-\frac {(b n) \int x \left (a+b \log \left (c x^n\right )\right ) \, dx}{e^2}\\ &=\frac {4 a b d n x}{e^3}+\frac {b^2 n^2 x^2}{4 e^2}-\frac {b n x^2 \left (a+b \log \left (c x^n\right )\right )}{2 e^2}-\frac {2 d x \left (a+b \log \left (c x^n\right )\right )^2}{e^3}+\frac {x^2 \left (a+b \log \left (c x^n\right )\right )^2}{2 e^2}-\frac {d^2 x \left (a+b \log \left (c x^n\right )\right )^2}{e^3 (d+e x)}+\frac {2 b d^2 n \left (a+b \log \left (c x^n\right )\right ) \log \left (1+\frac {e x}{d}\right )}{e^4}+\frac {3 d^2 \left (a+b \log \left (c x^n\right )\right )^2 \log \left (1+\frac {e x}{d}\right )}{e^4}+\frac {6 b d^2 n \left (a+b \log \left (c x^n\right )\right ) \text {Li}_2\left (-\frac {e x}{d}\right )}{e^4}+\frac {\left (4 b^2 d n\right ) \int \log \left (c x^n\right ) \, dx}{e^3}-\frac {\left (2 b^2 d^2 n^2\right ) \int \frac {\log \left (1+\frac {e x}{d}\right )}{x} \, dx}{e^4}-\frac {\left (6 b^2 d^2 n^2\right ) \int \frac {\text {Li}_2\left (-\frac {e x}{d}\right )}{x} \, dx}{e^4}\\ &=\frac {4 a b d n x}{e^3}-\frac {4 b^2 d n^2 x}{e^3}+\frac {b^2 n^2 x^2}{4 e^2}+\frac {4 b^2 d n x \log \left (c x^n\right )}{e^3}-\frac {b n x^2 \left (a+b \log \left (c x^n\right )\right )}{2 e^2}-\frac {2 d x \left (a+b \log \left (c x^n\right )\right )^2}{e^3}+\frac {x^2 \left (a+b \log \left (c x^n\right )\right )^2}{2 e^2}-\frac {d^2 x \left (a+b \log \left (c x^n\right )\right )^2}{e^3 (d+e x)}+\frac {2 b d^2 n \left (a+b \log \left (c x^n\right )\right ) \log \left (1+\frac {e x}{d}\right )}{e^4}+\frac {3 d^2 \left (a+b \log \left (c x^n\right )\right )^2 \log \left (1+\frac {e x}{d}\right )}{e^4}+\frac {2 b^2 d^2 n^2 \text {Li}_2\left (-\frac {e x}{d}\right )}{e^4}+\frac {6 b d^2 n \left (a+b \log \left (c x^n\right )\right ) \text {Li}_2\left (-\frac {e x}{d}\right )}{e^4}-\frac {6 b^2 d^2 n^2 \text {Li}_3\left (-\frac {e x}{d}\right )}{e^4}\\ \end {align*}

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Mathematica [A]
time = 0.14, size = 240, normalized size = 0.85 \begin {gather*} \frac {-8 d e x \left (a+b \log \left (c x^n\right )\right )^2+2 e^2 x^2 \left (a+b \log \left (c x^n\right )\right )^2+\frac {4 d^3 \left (a+b \log \left (c x^n\right )\right )^2}{d+e x}+16 b d e n x \left (a-b n+b \log \left (c x^n\right )\right )+b e^2 n x^2 \left (b n-2 \left (a+b \log \left (c x^n\right )\right )\right )+12 d^2 \left (a+b \log \left (c x^n\right )\right )^2 \log \left (1+\frac {e x}{d}\right )+4 d^2 \left (-\left (\left (a+b \log \left (c x^n\right )\right ) \left (a+b \log \left (c x^n\right )-2 b n \log \left (1+\frac {e x}{d}\right )\right )\right )+2 b^2 n^2 \text {Li}_2\left (-\frac {e x}{d}\right )\right )+24 b d^2 n \left (\left (a+b \log \left (c x^n\right )\right ) \text {Li}_2\left (-\frac {e x}{d}\right )-b n \text {Li}_3\left (-\frac {e x}{d}\right )\right )}{4 e^4} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(x^3*(a + b*Log[c*x^n])^2)/(d + e*x)^2,x]

[Out]

(-8*d*e*x*(a + b*Log[c*x^n])^2 + 2*e^2*x^2*(a + b*Log[c*x^n])^2 + (4*d^3*(a + b*Log[c*x^n])^2)/(d + e*x) + 16*
b*d*e*n*x*(a - b*n + b*Log[c*x^n]) + b*e^2*n*x^2*(b*n - 2*(a + b*Log[c*x^n])) + 12*d^2*(a + b*Log[c*x^n])^2*Lo
g[1 + (e*x)/d] + 4*d^2*(-((a + b*Log[c*x^n])*(a + b*Log[c*x^n] - 2*b*n*Log[1 + (e*x)/d])) + 2*b^2*n^2*PolyLog[
2, -((e*x)/d)]) + 24*b*d^2*n*((a + b*Log[c*x^n])*PolyLog[2, -((e*x)/d)] - b*n*PolyLog[3, -((e*x)/d)]))/(4*e^4)

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Maple [C] Result contains higher order function than in optimal. Order 9 vs. order 4.
time = 0.21, size = 4871, normalized size = 17.33

method	result	size
risch	\(\text {Expression too large to display}\)	\(4871\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^3*(a+b*ln(c*x^n))^2/(e*x+d)^2,x,method=_RETURNVERBOSE)

[Out]

1/e^2*x^2*ln(c)*a*b-2/e^3*d*x*ln(c)^2*b^2+3*I/e^4*n*ln(e*x+d)*ln(-e*x/d)*d^2*b^2*Pi*csgn(I*c)*csgn(I*x^n)*csgn
(I*c*x^n)+I*d^3/e^4/(e*x+d)*ln(c)*Pi*b^2*csgn(I*x^n)*csgn(I*c*x^n)^2+I*d^3/e^4/(e*x+d)*Pi*a*b*csgn(I*c)*csgn(I
*c*x^n)^2+I*d^3/e^4/(e*x+d)*Pi*a*b*csgn(I*x^n)*csgn(I*c*x^n)^2-1/2*I/e^2*x^2*Pi*a*b*csgn(I*c)*csgn(I*x^n)*csgn
(I*c*x^n)+1/4*I/e^2*n*x^2*b^2*Pi*csgn(I*c*x^n)^3+b^2/e^4*n^2*d^2*ln(x)^2-1/4*d^3/e^4/(e*x+d)*Pi^2*b^2*csgn(I*x
^n)^2*csgn(I*c*x^n)^4-6*b^2*n/e^4*d^2*ln(e*x+d)*ln(x^n)*ln(-e*x/d)-1/e^3*d*x*Pi^2*b^2*csgn(I*x^n)*csgn(I*c*x^n
)^5+1/4/e^2*x^2*Pi^2*b^2*csgn(I*c)^2*csgn(I*x^n)*csgn(I*c*x^n)^3+1/2*d^3/e^4/(e*x+d)*Pi^2*b^2*csgn(I*c)^2*csgn
(I*x^n)*csgn(I*c*x^n)^3+1/2/e^3*d*x*Pi^2*b^2*csgn(I*c)^2*csgn(I*x^n)^2*csgn(I*c*x^n)^2-1/e^3*d*x*Pi^2*b^2*csgn
(I*c)^2*csgn(I*x^n)*csgn(I*c*x^n)^3+3/2/e^4*d^2*ln(e*x+d)*Pi^2*b^2*csgn(I*c)^2*csgn(I*x^n)*csgn(I*c*x^n)^3+I*n
/e^4*d^2*ln(e*x)*b^2*Pi*csgn(I*c)*csgn(I*x^n)*csgn(I*c*x^n)+1/2*I/e^2*x^2*ln(c)*Pi*b^2*csgn(I*c)*csgn(I*c*x^n)
^2+1/2*I/e^2*x^2*ln(c)*Pi*b^2*csgn(I*x^n)*csgn(I*c*x^n)^2+9/4*I/e^4*d^2*n*b^2*Pi*csgn(I*c)*csgn(I*c*x^n)^2-1/4
*d^3/e^4/(e*x+d)*Pi^2*b^2*csgn(I*c*x^n)^6+1/4/e^2*x^2*Pi^2*b^2*csgn(I*x^n)*csgn(I*c*x^n)^5-1/8/e^2*x^2*Pi^2*b^
2*csgn(I*c)^2*csgn(I*c*x^n)^4+1/4/e^2*x^2*Pi^2*b^2*csgn(I*c)*csgn(I*c*x^n)^5-4/e^3*d*x*ln(c)*a*b+2*d^3/e^4/(e*
x+d)*ln(c)*a*b+6/e^4*d^2*ln(e*x+d)*ln(c)*a*b-1/2*I/e^2*x^2*ln(c)*Pi*b^2*csgn(I*c)*csgn(I*x^n)*csgn(I*c*x^n)+1/
2*a^2/e^2*x^2-2*a^2/e^3*d*x+3*a^2/e^4*d^2*ln(e*x+d)+a^2*d^3/e^4/(e*x+d)-1/2*b/e^2*n*x^2*a-6*b/e^4*n*dilog(-e*x
/d)*d^2*a-I*ln(x^n)*d^3/e^4/(e*x+d)*b^2*Pi*csgn(I*c*x^n)^3-6*b^2*n/e^4*d^2*ln(x^n)*dilog(-e*x/d)+4*b^2*n/e^3*l
n(x^n)*x*d-2*b^2*n/e^4*ln(x^n)*d^2*ln(x)+1/2*I/e^2*ln(x^n)*x^2*b^2*Pi*csgn(I*c)*csgn(I*c*x^n)^2+1/2*I/e^2*ln(x
^n)*x^2*b^2*Pi*csgn(I*x^n)*csgn(I*c*x^n)^2-6/e^4*n*ln(e*x+d)*ln(-e*x/d)*d^2*b^2*ln(c)+1/2/e^2*x^2*ln(c)^2*b^2+
I*n/e^4*d^2*ln(e*x)*b^2*Pi*csgn(I*c*x^n)^3+1/2*I/e^2*x^2*Pi*a*b*csgn(I*x^n)*csgn(I*c*x^n)^2+1/2*I/e^2*x^2*Pi*a
*b*csgn(I*c)*csgn(I*c*x^n)^2-2*I/e^3*n*x*d*b^2*Pi*csgn(I*c*x^n)^3+9/2*b/e^4*d^2*n*a+2*ln(x^n)*ln(e*x+d)*d^2/e^
4*b^2*n-4*b/e^3*ln(x^n)*x*d*a+6*b^2/e^4*d^2*ln(x)*ln(e*x+d)*ln(-e*x/d)*n^2-1/4*d^3/e^4/(e*x+d)*Pi^2*b^2*csgn(I
*c)^2*csgn(I*x^n)^2*csgn(I*c*x^n)^2+1/2*d^3/e^4/(e*x+d)*Pi^2*b^2*csgn(I*c)*csgn(I*x^n)^2*csgn(I*c*x^n)^3-6*b/e
^4*n*ln(e*x+d)*ln(-e*x/d)*d^2*a+3/2/e^4*d^2*ln(e*x+d)*Pi^2*b^2*csgn(I*c)*csgn(I*x^n)^2*csgn(I*c*x^n)^3-1/e^3*d
*x*Pi^2*b^2*csgn(I*c)*csgn(I*x^n)^2*csgn(I*c*x^n)^3+2/e^3*d*x*Pi^2*b^2*csgn(I*c)*csgn(I*x^n)*csgn(I*c*x^n)^4-3
/4/e^4*d^2*ln(e*x+d)*Pi^2*b^2*csgn(I*c)^2*csgn(I*x^n)^2*csgn(I*c*x^n)^2-3/e^4*d^2*ln(e*x+d)*Pi^2*b^2*csgn(I*c)
*csgn(I*x^n)*csgn(I*c*x^n)^4-d^3/e^4/(e*x+d)*Pi^2*b^2*csgn(I*c)*csgn(I*x^n)*csgn(I*c*x^n)^4+3*I/e^4*n*dilog(-e
*x/d)*d^2*b^2*Pi*csgn(I*c*x^n)^3-1/4*I/e^2*n*x^2*b^2*Pi*csgn(I*c)*csgn(I*c*x^n)^2-1/4*I/e^2*n*x^2*b^2*Pi*csgn(
I*x^n)*csgn(I*c*x^n)^2+2*I/e^3*d*x*ln(c)*Pi*b^2*csgn(I*c*x^n)^3+2*I/e^3*d*x*Pi*a*b*csgn(I*c*x^n)^3-4*b^2*d*n^2
*x/e^3-6*b^2*d^2*n^2*polylog(3,-e*x/d)/e^4+2*I/e^3*ln(x^n)*x*d*b^2*Pi*csgn(I*c*x^n)^3-3*I/e^4*d^2*ln(x^n)*ln(e
*x+d)*b^2*Pi*csgn(I*c*x^n)^3+6/e^4*d^2*ln(x^n)*ln(e*x+d)*b^2*ln(c)+2*ln(x^n)*d^3/e^4/(e*x+d)*b^2*ln(c)-4/e^3*l
n(x^n)*x*d*b^2*ln(c)+4*a*b*d*n*x/e^3-3*I/e^4*d^2*ln(e*x+d)*Pi*a*b*csgn(I*c*x^n)^3-3*I/e^4*d^2*ln(e*x+d)*ln(c)*
Pi*b^2*csgn(I*c*x^n)^3+6*b/e^4*d^2*ln(x^n)*ln(e*x+d)*a+2*b*ln(x^n)*d^3/e^4/(e*x+d)*a-1/2*I/e^2*x^2*ln(c)*Pi*b^
2*csgn(I*c*x^n)^3-2*b^2/e^4*n^2*dilog(-e*x/d)*d^2-6/e^4*n*dilog(-e*x/d)*d^2*b^2*ln(c)-2*n/e^4*d^2*ln(e*x)*b^2*
ln(c)+2*n/e^4*d^2*ln(e*x+d)*b^2*ln(c)+4/e^3*n*x*d*b^2*ln(c)-2*b*n/e^4*d^2*ln(e*x)*a+2*b*n/e^4*d^2*ln(e*x+d)*a+
1/2*b^2*ln(x^n)^2/e^2*x^2+6*b^2/e^4*d^2*ln(x)*dilog(-e*x/d)*n^2+1/2/e^3*d*x*Pi^2*b^2*csgn(I*c*x^n)^6-3/4/e^4*d
^2*ln(e*x+d)*Pi^2*b^2*csgn(I*c*x^n)^6-1/8/e^2*x^2*Pi^2*b^2*csgn(I*x^n)^2*csgn(I*c*x^n)^4-3*b^2/e^4*d^2*n^2*ln(
x)^2*ln(e*x+d)+3*b^2/e^4*d^2*n^2*ln(x)^2*ln(1+e*x/d)+6*b^2/e^4*d^2*n^2*ln(x)*polylog(2,-e*x/d)-2*b^2/e^4*n^2*l
n(e*x+d)*ln(-e*x/d)*d^2-I*n/e^4*d^2*ln(e*x+d)*b^2*Pi*csgn(I*c*x^n)^3-I*d^3/e^4/(e*x+d)*Pi*a*b*csgn(I*c*x^n)^3-
I*d^3/e^4/(e*x+d)*ln(c)*Pi*b^2*csgn(I*c*x^n)^3+9/4*I/e^4*d^2*n*b^2*Pi*csgn(I*x^n)*csgn(I*c*x^n)^2+3/2/e^4*d^2*
ln(e*x+d)*Pi^2*b^2*csgn(I*x^n)*csgn(I*c*x^n)^5+d^3/e^4/(e*x+d)*ln(c)^2*b^2+3/e^4*d^2*ln(e*x+d)*ln(c)^2*b^2+9/2
/e^4*d^2*n*b^2*ln(c)-1/2/e^2*n*x^2*b^2*ln(c)+3*I/e^4*d^2*ln(x^n)*ln(e*x+d)*b^2*Pi*csgn(I*c)*csgn(I*c*x^n)^2-3*
I/e^4*n*dilog(-e*x/d)*d^2*b^2*Pi*csgn(I*c)*csgn(I*c*x^n)^2+3*I/e^4*d^2*ln(e*x+d)*ln(c)*Pi*b^2*csgn(I*c)*csgn(I
*c*x^n)^2-1/8/e^2*x^2*Pi^2*b^2*csgn(I*c*x^n)^6+1/2/e^3*d*x*Pi^2*b^2*csgn(I*c)^2*csgn(I*c*x^n)^4+I*n/e^4*d^2*ln
(e*x+d)*b^2*Pi*csgn(I*c)*csgn(I*c*x^n)^2+I*d^3/e^4/(e*x+d)*ln(c)*Pi*b^2*csgn(I*c)*csgn(I*c*x^n)^2-I*n/e^4*d^2*
ln(e*x)*b^2*Pi*csgn(I*c)*csgn(I*c*x^n)^2-9/4*I/e^4*d^2*n*b^2*Pi*csgn(I*c)*csgn(I*x^n)*csgn(I*c*x^n)-1/2*I/e^2*
ln(x^n)*x^2*b^2*Pi*csgn(I*c)*csgn(I*x^n)*csgn(I*c*x^n)+3*I/e^4*n*ln(e*x+d)*ln(-e*x/d)*d^2*b^2*Pi*csgn(I*c*x^n)
^3-2*I/e^3*ln(x^n)*x*d*b^2*Pi*csgn(I*x^n)*csgn(...

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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^3*(a+b*log(c*x^n))^2/(e*x+d)^2,x, algorithm="maxima")

[Out]

1/2*(6*d^2*e^(-4)*log(x*e + d) + 2*d^3/(x*e^5 + d*e^4) + (x^2*e - 4*d*x)*e^(-3))*a^2 + integrate((b^2*x^3*log(
x^n)^2 + 2*(b^2*log(c) + a*b)*x^3*log(x^n) + (b^2*log(c)^2 + 2*a*b*log(c))*x^3)/(x^2*e^2 + 2*d*x*e + d^2), x)

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Fricas [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^3*(a+b*log(c*x^n))^2/(e*x+d)^2,x, algorithm="fricas")

[Out]

integral((b^2*x^3*log(c*x^n)^2 + 2*a*b*x^3*log(c*x^n) + a^2*x^3)/(x^2*e^2 + 2*d*x*e + d^2), x)

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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {x^{3} \left (a + b \log {\left (c x^{n} \right )}\right )^{2}}{\left (d + e x\right )^{2}}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**3*(a+b*ln(c*x**n))**2/(e*x+d)**2,x)

[Out]

Integral(x**3*(a + b*log(c*x**n))**2/(d + e*x)**2, x)

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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^3*(a+b*log(c*x^n))^2/(e*x+d)^2,x, algorithm="giac")

[Out]

integrate((b*log(c*x^n) + a)^2*x^3/(x*e + d)^2, x)

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Mupad [F]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int \frac {x^3\,{\left (a+b\,\ln \left (c\,x^n\right )\right )}^2}{{\left (d+e\,x\right )}^2} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((x^3*(a + b*log(c*x^n))^2)/(d + e*x)^2,x)

[Out]

int((x^3*(a + b*log(c*x^n))^2)/(d + e*x)^2, x)

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